Improve programmingMode to display results in binary (hexadecimal format) and prompt user for continuation

src/main/c/programmingMode.c

@@ -5,6 +5,10 @@
 
 #include "calculator.h"
 
+
+// Function to convert an integer to binary representation
+char* binaryRepresentation(int num);
+
 // get the NUmbers from the user
 int getIntegerInput(const char* prompt) {
     int num;
@@ -45,11 +49,52 @@ int performOperation(int num1, char operatorType, int num2) {
 
 void programmingMode() {
 
+char choice;
+    do {
         int num1 = getIntegerInput("Enter first integer: ");
         char operator = getOperatorInput();
         int num2 = getIntegerInput("Enter second integer: ");
 
-    // Calculation + Display the result
+        // Calculation
+        int result = performOperation(num1, operator, num2);
+
+        // Display the result in different bases based on user choice
+        int base;
+        printf("Choose base to print the result (2 for binary, 8 for octal, 16 for hexadecimal): ");
+        scanf("%d", &base);
+
+        switch (base) {
+            case 2:
+                printf("Result (Binary): %s\n", binaryRepresentation(result));
+                break;
+            case 8:
+                printf("Result (Octal): %o\n", result);
+                break;
+            case 16:
+                printf("Result (Hexadecimal): %x\n", result);
+                break;
+            default:
+                printf("Invalid base choice\n");
+                break;
+        }
+
+        // Ask user if they want to continue
+        printf("Do you want to continue? (y/n): ");
+        scanf(" %c", &choice);
 
-    printf("Result: %d\n", performOperation(num1, operator, num2));
+    } while (choice == 'y' || choice == 'Y');
 }
+
+
+
+// Function to convert an integer to binary representation
+char* binaryRepresentation(int num) {
+    static char binary[32];
+    for (int i = 31; i >= 0; i--) {
+        binary[i] = (num & 1) + '0';
+        num >>= 1;
+    }
+    binary[32] = '\0';
+    return binary;
+}
+