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@ -5,6 +5,10 @@ |
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#include "calculator.h" |
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#include "calculator.h" |
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// Function to convert an integer to binary representation |
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char* binaryRepresentation(int num); |
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// get the NUmbers from the user |
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// get the NUmbers from the user |
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int getIntegerInput(const char* prompt) { |
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int getIntegerInput(const char* prompt) { |
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int num; |
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int num; |
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@ -45,11 +49,52 @@ int performOperation(int num1, char operatorType, int num2) { |
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void programmingMode() { |
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void programmingMode() { |
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int num1 = getIntegerInput("Enter first integer: "); |
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char operator = getOperatorInput(); |
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int num2 = getIntegerInput("Enter second integer: "); |
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char choice; |
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do { |
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int num1 = getIntegerInput("Enter first integer: "); |
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char operator = getOperatorInput(); |
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int num2 = getIntegerInput("Enter second integer: "); |
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// Calculation |
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int result = performOperation(num1, operator, num2); |
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// Calculation + Display the result |
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// Display the result in different bases based on user choice |
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int base; |
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printf("Choose base to print the result (2 for binary, 8 for octal, 16 for hexadecimal): "); |
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scanf("%d", &base); |
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printf("Result: %d\n", performOperation(num1, operator, num2)); |
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switch (base) { |
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case 2: |
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printf("Result (Binary): %s\n", binaryRepresentation(result)); |
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break; |
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case 8: |
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printf("Result (Octal): %o\n", result); |
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break; |
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case 16: |
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printf("Result (Hexadecimal): %x\n", result); |
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break; |
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default: |
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printf("Invalid base choice\n"); |
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break; |
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} |
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// Ask user if they want to continue |
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printf("Do you want to continue? (y/n): "); |
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scanf(" %c", &choice); |
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} while (choice == 'y' || choice == 'Y'); |
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} |
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} |
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// Function to convert an integer to binary representation |
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char* binaryRepresentation(int num) { |
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static char binary[32]; |
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for (int i = 31; i >= 0; i--) { |
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binary[i] = (num & 1) + '0'; |
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num >>= 1; |
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} |
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binary[32] = '\0'; |
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return binary; |
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} |
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