Browse Source

kabrel conver_dectobin

remotes/origin/kabrel
fdai7801 11 months ago
parent
commit
39a09e24cd
  1. 62
      src/main/c/BasicMode.c

62
src/main/c/BasicMode.c

@ -2,58 +2,20 @@
#include <string.h>
#include <stdlib.h>
#include <math.h>
#include <stdio.h>
// convert decimal to binary
long long int DecToBin(long long int n) {
long long int bin = 0;
long long int rem, i = 1;
while (n != 0) {
rem = n % 2;
bin += rem * i;
i *= 10;
n /= 2;
}
void BasicMode() {
char endtmp = '0'; //0 false, 1 true
double result = 0;
double numbers[100] = {0.0};
char operators[100];
do {
//100 doubles in this array goes through the for loop till 100 numbers or = is entered
for (int i = 0; i < 100; i++) {
printf("Enter a Number: ");
numbers[i] = testForNumber(); //gets number
printf("Enter a operation: ");
operators[i] = testForOperator(); //gets operator
}
} while (endtmp != '1');
for (int i = 0; i < 100; i++) {//checks all operators to check for priority
if ((operators[i] == '/' || operators[i] == '*') && i > 1) { //if operators[i] == / or * and i>1 so you dont get numbers[-1]
if (operators[i] == '/') {
result += divide(numbers[i - 1], numbers[i]); //divides if char is / and adds number to the result
}
// for all calculations we take the number and the number before that
else { // and do the operation
result += multiply(numbers[i - 1], numbers[i]); //multiplys if char is * and adds number to the result
}
}
else if ((operators[i] == '+' || operators[i] == '-') && i > 1) {
if (operators[i] == '+') {
result += add(numbers[i - 1], numbers[i]); //adds if char is + and adds number to the result
}
else {
result += minus(numbers[i - 1], numbers[i]); //subtrakts if char is - and adds number to the result
}
}
else if (i<=1 && operators[i] == '=') { //if there are less then 2 numbers in the array
result = numbers[i]; //set result to the 0 digit
}
else if (operators[i] == '=') { //if char is =
printf("The result is: %f", result); //print out the result
i = 100;
break;
}
i++;
}
return bin;
}
Loading…
Cancel
Save