refactoring: rename function exponent and output and variables

src/addition.c

@@ -43,15 +43,15 @@ unsigned int precision(unsigned int number) {
 
 // reading exponent out of an integer (floating number)
 
-unsigned int e(unsigned int a) {
-    unsigned int e = 2139095040;
-    return (a & e) >> 23;
+unsigned int exponent(unsigned int number) {
+    unsigned int exponent = 2139095040;
+    return (number & exponent) >> 23;
 }
 
 // writing number out of sign, exponent and precision
 
-unsigned int o(unsigned int s, unsigned int e, unsigned int p) {
-    return (s << 31) | (e << 23) | p;
+unsigned int output(unsigned int sign, unsigned int exponent, unsigned int precision) {
+    return (sign << 31) | (exponent << 23) | precision;
 }
 
 // addition of two floating numbers

src/addition.h

@@ -11,9 +11,9 @@ unsigned int sign(unsigned int number);
 
 unsigned int precision(unsigned int number);
 
-unsigned int e(unsigned int a);
+unsigned int exponent(unsigned int number);
 
-unsigned int o(unsigned int s, unsigned int e, unsigned int p);
+unsigned int output(unsigned int sign, unsigned int exponent, unsigned int precision);
 
 float addition_float(float number1, float number2);
 

test/test_addition.c

@@ -176,11 +176,11 @@ void test_addition_exponentfloatingnumber(void)
     number[0].floating = 0, number[1].floating = -762134982, number[2].floating = 47621349, number[3].floating = -0.0000078961354, number[4].floating = 0.00001568943;
     unsigned int expected[5] = { ( number[0].integer << 1) >> 24 , ( number[1].integer << 1) >> 24, ( number[2].integer << 1) >> 24, ( number[3].integer << 1) >> 24, ( number[4].integer << 1) >> 24};
 
-    result[0] = e( number[0].integer );
-    result[1] = e( number[1].integer );
-    result[2] = e( number[2].integer );
-    result[3] = e( number[3].integer );
-    result[4] = e( number[4].integer );
+    result[0] = exponent( number[0].integer );
+    result[1] = exponent( number[1].integer );
+    result[2] = exponent( number[2].integer );
+    result[3] = exponent( number[3].integer );
+    result[4] = exponent( number[4].integer );
 
     TEST_ASSERT_EQUAL_UINT(expected[0], result[0]);
     TEST_ASSERT_EQUAL_UINT(expected[1], result[1]);
@@ -198,13 +198,13 @@ void test_addition_output_numberwithsignexponentprecision(void)
     unsigned int s0, s1, s2, s3, s4, e0, e1, e2, e3, e4, p0, p1, p2, p3, p4;
 
     s0 = sign(number[0].integer), s1 = sign(number[1].integer), s2 = sign(number[2].integer), s3 = sign(number[3].integer), s4 = sign(number[4].integer);
-    e0 = e(number[0].integer), e1 = e(number[1].integer), e2 = e(number[2].integer), e3 = e(number[3].integer), e4 = e(number[4].integer);
+    e0 = exponent(number[0].integer), e1 = exponent(number[1].integer), e2 = exponent(number[2].integer), e3 = exponent(number[3].integer), e4 = exponent(number[4].integer);
     p0 = precision(number[0].integer), p1 = precision(number[1].integer), p2 = precision(number[2].integer), p3 = precision(number[3].integer), p4 = precision(number[4].integer);
-    result[0] = o(s0, e0, p0);
-    result[1] = o(s1, e1, p1);
-    result[2] = o(s2, e2, p2);
-    result[3] = o(s3, e3, p3);
-    result[4] = o(s4, e4, p4);
+    result[0] = output(s0, e0, p0);
+    result[1] = output(s1, e1, p1);
+    result[2] = output(s2, e2, p2);
+    result[3] = output(s3, e3, p3);
+    result[4] = output(s4, e4, p4);
 
     TEST_ASSERT_EQUAL_UINT(expected[0], result[0]);
     TEST_ASSERT_EQUAL_UINT(expected[1], result[1]);