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testing: addition reading exponent out of double numbers

master
Dennis Sperzel 11 months ago
parent
commit
370f445b21
  1. 19
      test/test_addition.c

19
test/test_addition.c

@ -316,4 +316,23 @@ void test_addition_precision_double_numbers(void)
TEST_ASSERT_EQUAL_UINT64(expected[4], result[4]); TEST_ASSERT_EQUAL_UINT64(expected[4], result[4]);
} }
void test_addition_exponent_double_numbers(void)
{
unsigned long long result[5];
numberd[0].dnum = 830046503435461000, numberd[1].dnum = -906056810308432, numberd[2].dnum = 0.5315020335035034357, numberd[3].dnum = -34, numberd[4].dnum = 94315454312021310;
unsigned long long expected[5] = { (numberd[0].lnum << 1) >> 53 , (numberd[1].lnum << 1) >> 53, (numberd[2].lnum << 1) >> 53, (numberd[3].lnum << 1) >> 53, (numberd[4].lnum << 1) >> 53};
result[0] = exponent_double( numberd[0].lnum );
result[1] = exponent_double( numberd[1].lnum );
result[2] = exponent_double( numberd[2].lnum );
result[3] = exponent_double( numberd[3].lnum );
result[4] = exponent_double( numberd[4].lnum );
TEST_ASSERT_EQUAL_UINT64(expected[0], result[0]);
TEST_ASSERT_EQUAL_UINT64(expected[1], result[1]);
TEST_ASSERT_EQUAL_UINT64(expected[2], result[2]);
TEST_ASSERT_EQUAL_UINT64(expected[3], result[3]);
TEST_ASSERT_EQUAL_UINT64(expected[4], result[4]);
}
#endif // TEST #endif // TEST
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